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by Shachar Adam
Shachar Adam
Use of password only and not 2-way verification: While not using 2-factor authentication (2FA) increases risk, it does not necessarily constitute a clear vulnerability. It would be considered a security weakness or bad practice, but not necessarily a vulnerability by itself. This is why it's likely not included in the final answer. Using telnet to configure the system: Vulnerability: Telnet transmits data, including passwords, in plain text, making it susceptible to eavesdropping. It’s a known security risk, especially when configuring systems remotely. More secure alternatives like SSH should be used. Failure to keep activity logs: Vulnerability: Without activity logs, tracking unauthorized access or detecting security breaches becomes difficult. It is a significant vulnerability, as you would have no evidence of suspicious activity or intrusions. Using default passwords on networked devices: Vulnerability: Default passwords are well-known and easily exploitable by attackers. Failure to change default passwords is a classic security vulnerability. Answer 2, 3, 4: This suggests that the most severe vulnerabilities identified are those in answers 2, 3, and 4. All three involve clear, well-established vulnerabilities in system security. Everything: This would imply that all the items listed are vulnerabilities. However, as mentioned earlier, not using 2FA is more of a bad practice than a direct vulnerability, which is likely why this was not the correct answer.
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by Shachar Adam
Shachar Adam
Let's break down the problem and explain why the correct answer is as follows: Understanding DES-5 System: The encryption for DES-5 is structured as: 𝐶 = DEC 𝐾 1 ( ENC 𝐾 2 ( ENC 𝐾 3 ( DEC 𝐾 4 ( ENC 𝐾 5 ( 𝑀 ) ) ) ) ) C=DEC K1 ​ (ENC K2 ​ (ENC K3 ​ (DEC K4 ​ (ENC K5 ​ (M))))) Given: K2 = K3 and K4 = K5, this reduces the system to 3 unique keys: 𝐾 1 K1, 𝐾 2 / 𝐾 3 K2/K3, and 𝐾 4 / 𝐾 5 K4/K5. Since each key is 56 bits, brute-forcing a single key requires testing 2 56 2 56 possible keys. For DES-5, with 3 unique keys to brute-force, the total number of combinations is: Time complexity for DES-5 = 𝑂 ( 2 56 ) × 𝑂 ( 2 56 ) × 𝑂 ( 2 56 ) = 𝑂 ( 2 3 × 56 ) = 𝑂 ( 2 168 ) Time complexity for DES-5=O(2 56 )×O(2 56 )×O(2 56 )=O(2 3×56 )=O(2 168 ) Thus, the brute-force time complexity for DES-5 is O(2^168). Understanding DES-2 System: For the DES-2 system, it uses 2 unknown keys, each 56 bits long. To brute-force both keys, you would have to try all combinations of the two keys, resulting in a time complexity of: Time complexity for DES-2 = 𝑂 ( 2 56 ) × 𝑂 ( 2 56 ) = 𝑂 ( 2 2 × 56 ) = 𝑂 ( 2 112 ) Time complexity for DES-2=O(2 56 )×O(2 56 )=O(2 2×56 )=O(2 112 ) Thus, the brute-force time complexity for DES-2 is O(2^112). Answer: Method A (DES-5) has a brute-force time complexity of O(2^{168}), or O(2^{3 \times 56}). Method B (DES-2) has a brute-force time complexity of O(2^{112}), or O(2^{2 \times 56}). This matches the correct answer: Method A: O(2^{3 \times 56}) Method B: O(2^{2 \times 56})
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