שאלה | Review the following MIPS assembly code used in an interrupt handler: addi $sp, $sp, -8 # Adjust stack pointer for storing 2 registers sw $ra, 4($sp) # Save return address # Interrupt handling code begins mfc0 $t0, $13 # Move Cause register to $t0 to check interrupt cause jal print # [Interrupt Handling Code Continues] lw $ra, 4($sp) # Restore return address addi $sp, $sp, 8 # Restore stack pointer eret # Return from exception

Review the following MIPS assembly code used in an interrupt handler: addi $sp, $sp, -8 # Adjust stack pointer for storing 2 registers sw $ra, 4($sp) # Save return address # Interrupt handling code begins mfc0 $t0, $13 # Move Cause register to $t0 to check interrupt cause jal print # [Interrupt Handling Code Continues] lw $ra, 4($sp) # Restore return address addi $sp, $sp, 8 # Restore stack pointer eret # Return from exception

		The stack pointer should not be adjusted since the interrupt handler uses dedicated registers.
		The stack pointer adjustment is incorrect.
		The register $t0 is used without being saved first.
		The Cause register should not be moved to $t0.
		The eret instruction is unnecessary because the interrupt handler should end with a jr (jump register) instruction to return to the interrupted code.
		The return address is restored too early.

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